Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Cumulative Review - Page 114: 9c

Answer

$\frac{1}{12}$

Work Step by Step

$\frac{\sqrt x}{y}-\frac{y}{x}=\frac{\sqrt 4}{-3}-\frac{-3}{4}=-\frac{2}{3}+\frac{3}{4}=-\frac{8}{12}+\frac{9}{12}=\frac{1}{12}$
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