Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.4 - Partial Sums of Arithmetic and Geometric Sequences - Exercise Set - Page 660: 55



Work Step by Step

Using $(a+b)^3=a^3+3a^2b+3ab^2+b^3$ (or the cube of a binomial), the given expression, $ (2x-1)^3 ,$ is equivalent to \begin{array}{l}\require{cancel} (2x)^3+3(2x)^2(-1)+3(2x)(-1)^2+(-1)^3 \\\\= 8x^3+3(4x^2)(-1)+3(2x)(1)-1 \\\\= 8x^3-12x^2+6x-1 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.