Chapter 11 - Section 11.4 - Partial Sums of Arithmetic and Geometric Sequences - Exercise Set - Page 658: 23

$S_{10}=185$

Using $S_{n}=\dfrac{n}{2}(2a_1+(n-1)d)$, the sum of the first $ 10 $ terms of the sequence $ -4,1,6,...,41 $ is \begin{array}{l} S_{10}=\dfrac{10}{2}(2(-4)+(10-1)5)\\\\ S_{10}=5(-8+45)\\\\ S_{10}=5(37)\\\\ S_{10}=185 .\end{array}