Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Vocabulary, Readiness & Video Check - Page 638: 6



Work Step by Step

Substituting $n=1$ into the equation $ a_n=(-1)^n\cdot n^4 $ results to \begin{array}{l} a_1=(-1)^1\cdot 1^4 \\\\ a_1=-1 .\end{array}
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