Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set - Page 640: 56

Answer

multiple answers; see details

Work Step by Step

Given that $ a_n=\dfrac{\sqrt{n}}{\sqrt{n}+1} $, then, \begin{array}{l} a_1=\dfrac{\sqrt{1}}{\sqrt{1}+1} =\dfrac{1}{2} =0.5 ,\\\\ a_2=\dfrac{\sqrt{2}}{\sqrt{2}+1} \approx 0.5858 ,\\\\ a_3=\dfrac{\sqrt{3}}{\sqrt{3}+1} \approx 0.6340 ,\\\\ a_4=\dfrac{\sqrt{4}}{\sqrt{4}+1} \approx 0.6667 ,\\\\ a_5=\dfrac{\sqrt{5}}{\sqrt{5}+1} \approx 0.6910 .\end{array}
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