## Intermediate Algebra (6th Edition)

$(9y+x)+3z$
The associative property holds that $(a+b)+c=a+(b+c)$, where a, b, and c are real numbers. In this example, we can set $a+(b+c)=9y+(x+3z)$. So, $a=9y$, $b=x$, and $c=3z$. Therefore, the other side of this equation is $(a+b)+c=(9y+x)+3z$.