Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.2 - Algebraic Expressions and Sets of Numbers - Exercise Set - Page 16: 102

Answer

Every set is a subset of itself since every number in the set is included in itself.

Work Step by Step

If every set of set A is included in set B, set A is a subset of set B. Therefore, every set is a subset of itself since every number in the set is included in itself.
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