Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Test - Chapter R Test - Page 39: 11



Work Step by Step

We can use order of operations to perform the indicated operations. Step by step: $\frac{10-24+(-6)}{\sqrt 16(-5)}=\frac{10-24-6}{\sqrt16(-5)}=\frac{10-24-6}{4\times-5}=\frac{10-24-6}{-20}=\frac{-14-6}{-20}=\frac{-20}{-20}=1$ Recall that $\sqrt 16=4$, because $4^{2}=16$.
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