#### Answer

$3x-3y+3z$

#### Work Step by Step

The distributive property holds that $a(b+c)=ab+ac$ (for real numbers $a$, $b$, and $c$).
Therefore, $3(x-y+z)=3x+(3\times-y)+3z=3x-3y+3z$.

Published by
Pearson

ISBN 10:
0321969359

ISBN 13:
978-0-32196-935-4

$3x-3y+3z$

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