Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises - Page 31: 98

Answer

$(a)~48\times 3.2\times 0.075\div 190-2\times 0.015$ $(b)~0.031$

Work Step by Step

(a) We are given the formula: BAC=number of oz$\times\%alcohol\times 0.075\div$body weight in lb-hr of drinking $\times \mathrm{O}.015$ We plug in the values given: $=48\times 3.2\times 0.075\div 190-2\times 0.015$ (b) We evaluate using order of operations: $48\times 3.2\times 0.075\div 190-2\times 0.015$ First we multiply: $=153.6\times 0.075\div 190-2\times 0.015$ And multiply again: $=11.52\div 190-2\times 0.015$ Next we divide: $=0.061-2\times 0.015$ And multiply: $=0.061-0.03$ And subtract: $=0.031$
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