## Intermediate Algebra (12th Edition)

$(a)~48\times 3.2\times 0.075\div 190-2\times 0.015$ $(b)~0.031$
(a) We are given the formula: BAC=number of oz$\times\%alcohol\times 0.075\div$body weight in lb-hr of drinking $\times \mathrm{O}.015$ We plug in the values given: $=48\times 3.2\times 0.075\div 190-2\times 0.015$ (b) We evaluate using order of operations: $48\times 3.2\times 0.075\div 190-2\times 0.015$ First we multiply: $=153.6\times 0.075\div 190-2\times 0.015$ And multiply again: $=11.52\div 190-2\times 0.015$ Next we divide: $=0.061-2\times 0.015$ And multiply: $=0.061-0.03$ And subtract: $=0.031$