Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 22: 121


Take the reciprocal.

Work Step by Step

We notice that the two quotients of Exercises #118 and #117 are reciprocals of each other: $\displaystyle \frac{-0.5}{-1.5}=\frac{1}{\frac{-1.5}{-0.5}}$ Thus the answer to #118 must be the reciprocal of the answer to #117 ($\frac{1}{3}$). $\displaystyle \frac{1}{\frac{1}{3}}=3$
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