## Intermediate Algebra (12th Edition)

We notice that the two quotients of Exercises #118 and #117 are reciprocals of each other: $\displaystyle \frac{-0.5}{-1.5}=\frac{1}{\frac{-1.5}{-0.5}}$ Thus the answer to #118 must be the reciprocal of the answer to #117 ($\frac{1}{3}$). $\displaystyle \frac{1}{\frac{1}{3}}=3$