Answer
Graph of $
f(x)=\sqrt{x},\text{ }x\ge0
$ (blue) and $f^{-1}(x)$ (red, dashed)
Work Step by Step
Substituting the given values of $x$ in the given function, $
f(x)=\sqrt{x},\text{ }x\ge0
$, results to
\begin{array}{c|c|c}
\text{If }x=0: & \text{If }x=1 & \text{If }x=4
\\\\
f(x)=y=\sqrt{x} & f(x)=y=\sqrt{x} & f(x)=y=\sqrt{x}
\\
y=\sqrt{0} & y=\sqrt{1} & y=\sqrt{4}
\\
y=0 & y=1 & y=2
.\end{array}
Tabulating the results above results to the table below.
\begin{array}{c|c}
\hline
x & f(x)
\\\hline
0 & 0
\\\hline
1 & 1
\\\hline
4 & 2
\\\hline
\end{array}
Connecting the points $
(0,0),(1,1) \text{ and } (4,2)
$ with a curve gives the graph of $
f(x)=\sqrt{x},\text{ }x\ge0
$ (blue graph).
Interchanging the $x$ and $y$ coordinates of the points above gives the graph of the inverse function. That is, connecting the points $
(0,0), (1,1) \text{ and } (2,4)
$ determines the graph of the inverse function (red dashed line).