#### Answer

$(5,6)$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
To find the vertex of the given quadratic function, $
f(x)=-(x-5)^2+6
,$ identify $h$ and $k$ of the function $f(x)=a(x-h)^2+k.$ The vertex is located at $(h,k).$
$\bf{\text{Solution Details:}}$
In the function above, $h=
5
$ and $k=
6
.$ Hence, the vertex is
\begin{array}{l}\require{cancel}
(5,6)
.\end{array}