## Intermediate Algebra (12th Edition)

$x=\left\{ -3-\sqrt{11},-3+\sqrt{11} \right\}$
$\bf{\text{Solution Outline:}}$ To solve the given equation, $(x+3)^2=11 ,$ take the square root of both sides (Square Root Property). Then use the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Taking the square root of both sides (Square Root Property), the equation above is equivalent to \begin{array}{l}\require{cancel} x+3=\pm\sqrt{11} .\end{array} Using the properties of equality to isolate the variable, the equation above is equivalent to \begin{array}{l}\require{cancel} x=-3\pm\sqrt{11} .\end{array} The solutions are \begin{array}{l}\require{cancel} x=-3-\sqrt{11} \\\\\text{OR}\\\\ x=-3+\sqrt{11} .\end{array} Hence, $x=\left\{ -3-\sqrt{11},-3+\sqrt{11} \right\} .$