## Intermediate Algebra (12th Edition)

$\dfrac{5\sqrt{2my}}{y^2}$
$\bf{\text{Solution Outline:}}$ To rationalize the given radical expression, $\dfrac{5\sqrt{2m}}{\sqrt{y^3}} ,$ multiply the numerator and the denominator by an expression equal to $1$ which will make the denominator a perfect power of the index. $\bf{\text{Solution Details:}}$ Multiplying the numerator and the denominator by an expression equal to $1$ which will make the denominator a perfect power of the index results to \begin{array}{l}\require{cancel} \dfrac{5\sqrt{2m}}{\sqrt{y^3}}\cdot\dfrac{\sqrt{y}}{\sqrt{y}} .\end{array} Using the Product Rule of radicals which is given by $\sqrt[m]{x}\cdot\sqrt[m]{y}=\sqrt[m]{xy},$ the expression above is equivalent to\begin{array}{l}\require{cancel} \dfrac{5\sqrt{2m(y)}}{\sqrt{y^3(y)}} \\\\= \dfrac{5\sqrt{2my}}{\sqrt{y^4}} \\\\= \dfrac{5\sqrt{2my}}{\sqrt{(y^2)^2}} .\end{array} Extracting the root of the radicand that is a perfect power of the index results to \begin{array}{l}\require{cancel} \dfrac{5\sqrt{2my}}{y^2} .\end{array}