Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises: 137

Answer

$(x+8)^2+(y+5)^2=5$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the Center-Radius Form of the equation of circles to get the equation with the given center, $C( -8,-5 ),$ and the given radius, $r= \sqrt{5} .$ $\bf{\text{Solution Details:}}$ With the given center, then $h= -8 $ and $k= -5 .$ Using the Center-Radius Form of the equation of circles which is given by $(x-h)^2+(y-k)^2=r^2, $ the equation of the circle is \begin{array}{l}\require{cancel} (x-(-8))^2+(y-(-5))^2=(\sqrt{5})^2 \\\\ (x+8)^2+(y+5)^2=5 .\end{array}
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