#### Answer

$y^{3/2}$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
Use the definition of rational exponents and the laws of exponents to simplify the given expression, $
\sqrt[6]{y^5}\cdot\sqrt[3]{y^2}
.$
$\bf{\text{Solution Details:}}$
Using the definition of rational exponents which is given by $a^{\frac{m}{n}}=\sqrt[n]{a^m}=\left(\sqrt[n]{a}\right)^m,$ the expression above is equivalent to
\begin{array}{l}\require{cancel}
y^{5/6}\cdot y^{2/3}
.\end{array}
Using the Product Rule of the laws of exponents which is given by $x^m\cdot x^n=x^{m+n},$ the expression above is equivalent to
\begin{array}{l}\require{cancel}
y^{\frac{5}{6}+\frac{2}{3}}
.\end{array}
To simplify the expression $
\dfrac{5}{6}+\dfrac{2}{3}
,$ change the expressions to similar fractions (same denominator) by using the $LCD$. The $LCD$ of the denominators $
6
$ and $
3
$ is $
6
$ since it is the lowest number that can be exactly divided by the denominators. Multiplying the terms by an expression equal to $1$ that will make the denominator equal to the $LCD$ results to
\begin{array}{l}\require{cancel}
y^{\frac{5}{6}+\frac{2}{3}\cdot\frac{2}{2}}
\\\\=
y^{\frac{5}{6}+\frac{4}{6}}
\\\\=
y^{\frac{9}{6}}
\\\\=
y^{\frac{3}{2}}
\\\\=
y^{3/2}
.\end{array}