Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Review Exercises: 42



Work Step by Step

We are given that $(\sqrt[n] a)^{m}=\sqrt[n] a^{m}=a^{\frac{m}{n}}$, as long as all indicated roots are real numbers. Therefore, $\sqrt[6] r^{9}=r^{\frac{9}{6}}=r^{\frac{9\div3}{6\div3}}=r^{\frac{3}{2}}$.
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