#### Answer

$(x-10)(x^2+10x+100)$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
To factor the given expression, $
x^3-1000
,$ use the factoring of the sum or difference of $2$ cubes.
$\bf{\text{Solution Details:}}$
The expressions $
x^3
$ and $
1000
$ are both perfect cubes (the cube root is exact). Hence, $
x^3-1000
$ is a $\text{
difference
}$ of $2$ cubes. Using the factoring of the sum or difference of $2$ cubes which is given by $a^3+b^3=(a+b)(a^2-ab+b^2)$ or by $a^3-b^3=(a-b)(a^2+ab+b^2)$ the expression above is equivalent to
\begin{array}{l}\require{cancel}
(x)^3-(10)^3
\\\\=
(x-10)[(x)^2+x(10)+(10)^2]
\\\\=
(x-10)(x^2+10x+100)
.\end{array}