Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 5 - Section 5.1 - Greatest Common Factors and Factoring by Grouping - 5.1 Exercises: 53

Answer

$(p+q)(p-4z)$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Group the terms of the given expression, $ p^2-4zq+pq-4pz ,$ such that the factored form of the groupings will result to a factor common to the entire expression. Then, factor the $GCF$ in each group. Finally, factor the $GCF$ of the entire expression. $\bf{\text{Solution Details:}}$ Grouping the first and third terms and the second and fourth terms, the given expression is equivalent to \begin{array}{l}\require{cancel} (p^2+pq)-(4zq+4pz) .\end{array} Factoring the $GCF$ in each group, results to \begin{array}{l}\require{cancel} p(p+q)-4z(q+p) \\\\= p(p+q)-4z(p+q) .\end{array} Factoring the $GCF= (p+q) $ of the entire expression above results to \begin{array}{l}\require{cancel} (p+q)(p-4z) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.