Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 5 - Section 5.1 - Greatest Common Factors and Factoring by Grouping - 5.1 Exercises: 47

Answer

$(m+q)(x+y)$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Factor by grouping the first $2$ and the last $2$ terms of the given expression, $ mx+qx+my+qy .$ Then, factor the $GCF$ in each group. Finally, factor the $GCF$ of the entire expression. $\bf{\text{Solution Details:}}$ Grouping the first $2$ and the last $2$ terms, the given expression is equivalent to\begin{array}{l}\require{cancel} (mx+qx)+(my+qy) .\end{array} Factoring the $GCF$ in each group, results to \begin{array}{l}\require{cancel} x(m+q)+y(m+q) .\end{array} Factoring the $GCF= (m+q) $ of the entire expression above results to \begin{array}{l}\require{cancel} (m+q)(x+y) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.