Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 5 - Review Exercises - Page 360: 23

Answer

$(y^2-6)(x^2+5) $

Work Step by Step

To factor means to convert an expression into expressions that are multiplied. The given expression, $ x^2(y^2-6)+5(y^2-6) ,$ are not expressions that are multiplied. To factor this, factor the common expression, $(y^2-6)$. This results to \begin{array}{l}\require{cancel} (y^2-6)(x^2+5) .\end{array}
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