Answer
$5y^2 \left( 3y+4 \right)$
Work Step by Step
$\bf{\text{Solution Outline:}}$
Get the $GCF$ of the given expression, $
15y^3+20y^2
.$ Divide the given expression and the $GCF.$ Express the answer as the product of the $GCF$ and the resulting quotient.
$\bf{\text{Solution Details:}}$
The $GCF$ of the constants of the terms $\{
15,20
\}$ is $
5
$ since it is the highest number that can divide all the given constants. The $GCF$ of the common variable/s is the variable/s with the lowest exponent. Hence, the $GCF$ of the common variable/s $\{
y^3,y^2
\}$ is $
y^2
.$ Hence, the entire expression has $GCF=
5y^2
.$
Factoring the $GCF=
5y^2
,$ the expression above is equivalent to
\begin{array}{l}\require{cancel}
5y^2 \left( \dfrac{15y^3}{5y^2}+\dfrac{20y^2}{5y^2} \right)
\\\\=
5y^2 \left( 3y+4 \right)
.\end{array}
