Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 5 - Chapter 5 Test: 18

Answer

$r=\dfrac{-6t-2}{a-3}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ ar+2=3r-6t ,$ for $ r ,$ put all variables with $ r $ on the left side of the equation and all other terms on the right side. Then use the properties of equality to isolate $ r .$ $\bf{\text{Solution Details:}}$ Putting all terms with $r$ on the left side of the equation and all other terms on the right side, the equation above is equivalent to \begin{array}{l}\require{cancel} ar-3r=-6t-2 .\end{array} Factoring $r$ on the left side and then isolating it result to \begin{array}{l}\require{cancel} r(a-3)=-6t-2 \\\\ r=\dfrac{-6t-2}{a-3} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.