## Intermediate Algebra (12th Edition)

$r=\dfrac{-6t-2}{a-3}$
$\bf{\text{Solution Outline:}}$ To solve the given equation, $ar+2=3r-6t ,$ for $r ,$ put all variables with $r$ on the left side of the equation and all other terms on the right side. Then use the properties of equality to isolate $r .$ $\bf{\text{Solution Details:}}$ Putting all terms with $r$ on the left side of the equation and all other terms on the right side, the equation above is equivalent to \begin{array}{l}\require{cancel} ar-3r=-6t-2 .\end{array} Factoring $r$ on the left side and then isolating it result to \begin{array}{l}\require{cancel} r(a-3)=-6t-2 \\\\ r=\dfrac{-6t-2}{a-3} .\end{array}