Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.3 - Polynomial Functions, Graphs, and Composition - 4.3 Exercises - Page 296: 68



Work Step by Step

We are asked to find $(g∘g)(1)$. We know that $(g∘g)(x)=g(g(x))$. Therefore, $(g∘g)(1)=g(g(1))$. From the first table, we see that $g(1)=9$. From the first table, we see that $g(9)=12$. Therefore, $g(g(1))=g(9)=12$.
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