Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Chapters R-4 - Cumulative Review Exercises: 22

Answer

$g(3)=-9$

Work Step by Step

Substituting $x=3$ in the given function $g(x)=-x^2-2x+6,$ then $g(3)$ evaluates to \begin{array}{l}\require{cancel} g(3)=-(3)^2-2(3)+6 \\\\ g(3)=-9-6+6 \\\\ g(3)=-9 .\end{array}
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