## Intermediate Algebra (12th Edition)

First equation: $3x+7y=4$ $7y=-3x+4$ $y=-\frac{3}{7}x+\frac{4}{7}$ Second equation: $6x+14y=3$ $14y=-6x+3$ $y=-\frac{6}{14}+3\frac{3}{14}=-\frac{3}{7}x+\frac{3}{14}$ This means that the equations have the same slopes, but different y-intercepts. Therefore, the system is inconsistent, there are no solutions.