## Intermediate Algebra (12th Edition)

$y=-8$
Using $y-y_1=m(x-x_1)$ or the point-slope form of linear equations, the equation of the line passing through $( 5,-8 )$ and with a slope of $m= 0$ is \begin{array}{l}\require{cancel} y-(-8)=0(x-5) \\\\ y+8=0 .\end{array} In the form $y=mx+b$, the equation above is equivalent to \begin{array}{l}\require{cancel} y+8=0 \\\\ y=-8 .\end{array} In the form $Ax+By=C$, the equation above is equivalent to \begin{array}{l}\require{cancel} y=-8 .\end{array} Hence, the different forms of the equation of the line with the given conditions are \begin{array}{l}\require{cancel} \text{slope-intercept form: } y=-8 \\\\ \text{standard form: } y=-8 .\end{array}