#### Answer

$m=-\dfrac{3}{2}$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
Use the Slope Formula to find the slope of the line that passes through $(-1,5)$ and $(3,-1).$
$\bf{\text{Solution Details:}}$
With the given points,
\begin{array}{l}\require{cancel}
y_1=
5
,\\y_2=
-1
,\\x_1=
-1
,\text{ and }\\ x_2=
3
.\end{array}
Using $m=\dfrac{y_1-y_2}{x_1-x_2}$ or the Slope Formula, the slope, $m,$ of the line is
\begin{array}{l}\require{cancel}
m=\dfrac{y_1-y_2}{x_1-x_2}
\\\\
m=\dfrac{5-(-1)}{-1-3}
\\\\
m=\dfrac{5+1}{-1-3}
\\\\
m=\dfrac{6}{-4}
\\\\
m=-\dfrac{3}{2}
.\end{array}