#### Answer

$C=10^{\mathrm{o}}$

#### Work Step by Step

We got this equation in Exercise 101:
$C=\displaystyle \frac{5}{9}(F-32)$
We plug in $F=50$ and solve for $C$:
$C=\displaystyle \frac{5}{9}(50-32)$
$=\frac{5}{9}(18)$
$=10^{\mathrm{o}}$

Published by
Pearson

ISBN 10:
0321969359

ISBN 13:
978-0-32196-935-4

$C=10^{\mathrm{o}}$

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