Answer
$C=10^{\mathrm{o}}$
Work Step by Step
We got this equation in Exercise 101:
$C=\displaystyle \frac{5}{9}(F-32)$
We plug in $F=50$ and solve for $C$:
$C=\displaystyle \frac{5}{9}(50-32)$
$=\frac{5}{9}(18)$
$=10^{\mathrm{o}}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 2 - Section 2.3 - Writing Equations of Lines - 2.3 Exercises - Page 176: 103
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