Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.1 - Linear Equations in Two Variables - 2.1 Exercises - Page 146: 79



Work Step by Step

To find the midpoint between points $(x_1,y_1)$ and $(x_2,y_2)$, we use the midpoint formula: $\displaystyle Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$ We have the two points, $P(1.5,1.25)$ and $Q(x,y)$. The midpoint is $M(3,1)$. Thus we have: $\displaystyle Midpoint=(\frac{1.5+x}{2},\ \frac{1.25+y}{2})=(3,1)$ We solve for $x$: $\frac{1.5+x}{2}=3$ $1.5+x=6$ $x=4.5$ And for $y$: $\frac{1.25+y}{2}=1$ $1.25+y=2$ $y=2-1.25$ $y=0.75$ Therefore, the point Q is: $(4.5,0.75)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.