#### Answer

at least two points; (3,2) and (6,4).

#### Work Step by Step

We need at least two points to graph a line.
To find the point $(3,y)$, we plug in $x=3$ and solve for $y$:
$2x-3y=0$
$2*3-3y=0$
$6-3y=0$
$3y=6$
$y=2$
Similarly, to find the point $(x,4)$, we plug in $y=4$ and solve for $x$:
$2x-3y=0$
$2x-3*4=0$
$2x=12$
$x=6$
Thus the points $(3,2)$ and $(6,4)$ lie on the graph of $2x-3y=0$.