Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Review Exercises - Page 211: 53



Work Step by Step

We are given that $f(x)=-2x^{2}+3x-6$. In order to evaluate at $f(-\frac{1}{2})$, we can plug $-\frac{1}{2}$ into the function and evaluate. $f(-\frac{1}{2})=-2(-\frac{1}{2})^{2}+3(-\frac{1}{2})-6=-2(\frac{1}{4})-\frac{3}{2}-6=-\frac{2}{4}-\frac{3}{2}-6=-\frac{2}{4}-\frac{6}{4}-\frac{24}{4}=\frac{-2-6-24}{4}=\frac{-32}{4}=-8$
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