Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Chapters R-2 - Cumulative Review Exercises - Page 213: 6

Answer

$8i$

Work Step by Step

The given expression, $ \sqrt{-64} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt{-1}\cdot\sqrt{64} \\\\= i \cdot\sqrt{(8)^2} \\\\= 8i .\end{array}
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