Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Chapter 2 Test: 1

Answer

see graph
1514034537

Work Step by Step

$\bf{\text{Solution Outline:}}$ Substitute the given value of the variable in the given equation, $ 2x-3y=12 ,$ to complete the table. $\bf{\text{Solution Details:}}$ If $x=1,$ then \begin{array}{l}\require{cancel} 2x-3y=12 \\\\ 2(1)-3y=12 \\\\ 2-3y=12 \\\\ -3y=12-2 \\\\ -3y=10 \\\\ y=\dfrac{10}{-3} \\\\ y=-\dfrac{10}{3} .\end{array} If $x=3,$ then \begin{array}{l}\require{cancel} 2x-3y=12 \\\\ 2(3)-3y=12 \\\\ 6-3y=12 \\\\ -3y=12-6 \\\\ -3y=6 \\\\ y=\dfrac{6}{-3} \\\\ y=-2 .\end{array} If $y=-4,$ then \begin{array}{l}\require{cancel} 2x-3y=12 \\\\ 2x-3(-4)=12 \\\\ 2x+12=12 \\\\ 2x=12-12 \\\\ 2x=0 \\\\ x=\dfrac{0}{2} \\\\ x=0 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.