Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Section 1.2 - Formulas and Percent - 1.2 Exercises - Page 63: 49


$\%~alcohol=25\%$ $\%~water=75\%$

Work Step by Step

We know that: $alcohol+water=36$ oz And that: $alcohol=9$ oz To find the percent alcohol, we use: $\%~alcohol=\frac{alcohol}{alcohol+water}=\frac{9}{36}=0.25=25\%$ That means that the percent water is: $\% water+\% alcohol=100$ $\% water=100-\% alcohol=100-25=75\%$
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