## Intermediate Algebra (12th Edition)

$\%~alcohol=25\%$ $\%~water=75\%$
We know that: $alcohol+water=36$ oz And that: $alcohol=9$ oz To find the percent alcohol, we use: $\%~alcohol=\frac{alcohol}{alcohol+water}=\frac{9}{36}=0.25=25\%$ That means that the percent water is: $\% water+\% alcohol=100$ $\% water=100-\% alcohol=100-25=75\%$