## Intermediate Algebra (12th Edition)

We can see that the equation $h=\frac{2A}{b}$ is not equivalent to (D), $h=\frac{\frac{1}{2}A}{b}$: $\frac{2A}{b}\stackrel{?}{=}\frac{\frac{1}{2}A}{b}$ Multiply by $b$: $b(\frac{2A}{b})\stackrel{?}{=}b(\frac{\frac{1}{2}A}{b})$ $2A\stackrel{?}{=}\frac{1}{2}A$ Divide by A: $(2A)/A\stackrel{?}{=}(\frac{1}{2}A)/A$ $2\stackrel{?}{=}\frac{1}{2}$ $2\ne \frac{1}{2}$ This is clearly false, so the equation is not equivalent to D.