## Intermediate Algebra (12th Edition)

a) $b=\dfrac{2A-hB}{h}$ b) $B=\dfrac{2A-hb}{h}$
a) Using the properties of equality, in terms of $b ,$ the given formula, $A=\dfrac{1}{2}h(b+B) ,$ is equivalent to \begin{array}{l}\require{cancel} 2A=h(b+B) \\\\ 2A=hb+hB \\\\ 2A-hB=hb \\\\ \dfrac{2A-hB}{h}=b \\\\ b=\dfrac{2A-hB}{h} .\end{array} b) Using the properties of equality, in terms of $B ,$ the given formula, $A=\dfrac{1}{2}h(b+B) ,$ is equivalent to \begin{array}{l}\require{cancel} 2A=h(b+B) \\\\ 2A=hb+hB \\\\ 2A-hb=hB \\\\ \dfrac{2A-hb}{h}=B \\\\ B=\dfrac{2A-hb}{h} .\end{array}