Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 1 - Section 1.2 - Formulas and Percent - 1.2 Exercises: 15

Answer

a) $b=\dfrac{2A-hB}{h}$ b) $B=\dfrac{2A-hb}{h}$

Work Step by Step

a) Using the properties of equality, in terms of $ b ,$ the given formula, $ A=\dfrac{1}{2}h(b+B) ,$ is equivalent to \begin{array}{l}\require{cancel} 2A=h(b+B) \\\\ 2A=hb+hB \\\\ 2A-hB=hb \\\\ \dfrac{2A-hB}{h}=b \\\\ b=\dfrac{2A-hB}{h} .\end{array} b) Using the properties of equality, in terms of $ B ,$ the given formula, $ A=\dfrac{1}{2}h(b+B) ,$ is equivalent to \begin{array}{l}\require{cancel} 2A=h(b+B) \\\\ 2A=hb+hB \\\\ 2A-hb=hB \\\\ \dfrac{2A-hb}{h}=B \\\\ B=\dfrac{2A-hb}{h} .\end{array}
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