Answer
$9$
Work Step by Step
We know that $ai+bj+ck=(a,b,c).$
We know that for a matrix
$
\left[\begin{array}{rrr}
a & b & c \\
d &e & f \\
g &h & i \\
\end{array} \right]
$
the determinant, $D=a(ei-fh)-b(di-fg)+c(dh-eg).$
$v×w$ is the determinant of the matrix $\begin{bmatrix}
i& j & k \\
0& 3&3\\
3&0 &3 \\
\end{bmatrix}
$
Thus $v×w=(9,9,-9).$
Thus
$u\cdot (v\times w)=(1,1,3)(9,9,-9)=9+9-27=-9$
Thus,
Area$=|u\cdot (v\times w)|=|-9|=9$
