Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 5 - Inner Product Spaces - 5.4 Mathematical Models and Least Squares Analysis - 5.4 Exercises - Page 269: 10


$u=(0,1)$, then $\langle u.u\rangle=\langle (0,1).(0,1)\rangle=-2<0$.

Work Step by Step

Let $u=(0,1)$, then $\langle u.u\rangle=\langle (0,1).(0,1)\rangle=-2<0$. This shows that the function does not satisfy the conditions of the inner product.
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