## Elementary Linear Algebra 7th Edition

$$\left[ \begin{array}{ccc} 2&-1&-1\\ 1&3&2\\-6&3&3\end{array} \right]=0.$$
Given $$\left[ \begin{array}{ccc} 2&-1&-1\\ 1&3&2\\-6&3&3\end{array} \right].$$ Since the third row is the multiple of the first row by $-3$, then we have $$\left[ \begin{array}{ccc} 2&-1&-1\\ 1&3&2\\-6&3&3\end{array} \right]=0.$$