Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 3 - Determinants - 3.2 Determinants and Elementary Operations - 3.2 Exercises - Page 118: 27

Answer

$$ \left[ \begin{array}{ccc} 2&-1&-1\\ 1&3&2\\-6&3&3\end{array} \right]=0. $$

Work Step by Step

Given $$ \left[ \begin{array}{ccc} 2&-1&-1\\ 1&3&2\\-6&3&3\end{array} \right]. $$ Since the third row is the multiple of the first row by $-3$, then we have $$ \left[ \begin{array}{ccc} 2&-1&-1\\ 1&3&2\\-6&3&3\end{array} \right]=0. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.