Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 2 - Matrices - 2.1 Operations with Matrices - 2.1 Exercises - Page 49: 59

Answer

$$AB=\left[\begin{array}{rrr}{-10} & {0} \\ {0} & {-12} \end{array}\right] .$$ $$BA=\left[\begin{array}{rrr}{-10} & {0} \\ {0} & {-12} \end{array}\right] .$$

Work Step by Step

Given $$ A=\left[\begin{array}{rr}{2} & {0} \\ {0} & {-3}\end{array}\right], \quad B=\left[\begin{array}{rr}{-5} & {0} \\ {0} & {4}\end{array}\right] $$ We have \begin{align*} AB&= \left[\begin{array}{rr}{2} & {0} \\ {0} & {-3}\end{array}\right]\left[\begin{array}{rr}{-5} & {0} \\ {0} & {4}\end{array}\right]\\ &=\left[\begin{array}{rrr}{-10} & {0} \\ {0} & {-12} \end{array}\right] . \end{align*} \begin{align*} BA&= \left[\begin{array}{rr}{-5} & {0} \\ {0} & {4}\end{array}\right]\left[\begin{array}{rr}{2} & {0} \\ {0} & {-3}\end{array}\right]\\ &=\left[\begin{array}{rrr}{-10} & {0} \\ {0} & {-12} \end{array}\right] . \end{align*}
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