#### Answer

This system is inconsistent - it has no solutions.

#### Work Step by Step

Follow the steps below:
Step 1: Substitute from the third equation the first one multiplied by $3$:
$$3x-3x-2y-2y=8-0$$ which becomes $$-4y=8$$ and this gives $$y=-2.$$
Step 2: Substitute from the second equation the first one to eliminate $x$:
$$x-x+y-2y=6-0$$ which becomes $$-y=6\Rightarrow y=-6.$$
Now since $y$ cannot be both $-6$ and $-2$ we see that this system is inconsistent and has no solutions.