Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises: 53

Answer

This system is contradictory and has no solutions.

Work Step by Step

To transform this system to Row-Echelon form we will follows the steps bellow. Step 1: Subtract from the second equation the first one multiplied by $5$ term by term to eliminate $x$: $$5x-5x-15y-5\times(-3y) + 10z - 5\times 2 z = 18-5\times 18$$ which becomes $$0=-72.$$ What we got here in impossible which means that this system is contradictory and has no solutions.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.