## Elementary Linear Algebra 7th Edition

Published by Cengage Learning

# Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises: 53

#### Answer

This system is contradictory and has no solutions.

#### Work Step by Step

To transform this system to Row-Echelon form we will follows the steps bellow. Step 1: Subtract from the second equation the first one multiplied by $5$ term by term to eliminate $x$: $$5x-5x-15y-5\times(-3y) + 10z - 5\times 2 z = 18-5\times 18$$ which becomes $$0=-72.$$ What we got here in impossible which means that this system is contradictory and has no solutions.

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