Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.4 Polynomials - R.4 Exercise Set: 6

Answer

$-\dfrac{1}{8}$

Work Step by Step

Using $a^{-n}=\dfrac{1}{a^n}$, the given expression, $ (-2)^{-3} ,$ simplifies to: \begin{array}{l}\require{cancel} \dfrac{1}{(-2)^{3}} \\\\= \dfrac{1}{-8} \\\\= -\dfrac{1}{8} \end{array}
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