Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 9 - Inequalities and Problem Solving - Test: Chapter 9 - Page 624: 11


$\left(- \infty, 2 \right]$

Work Step by Step

$\bf{\text{Solution Outline:}}$ The domain of the given function, $ f(x)=\sqrt{6-3x} ,$ is all the values of $x$ for which the radicand is greater than or equal to $0.$ Express the answer in the interval notation. $\bf{\text{Solution Details:}}$ Since the radicand should be greater than or equal to zero, then \begin{array}{l}\require{cancel} 6-3x\ge0 \\\\ -3x\ge-6 .\end{array} Dividing both sides by a negative number (and consequently reversing the inequality symbol), the inequality above is equivalent to \begin{array}{l}\require{cancel} -3x\ge-6 \\\\ x\le\dfrac{-6}{-3} \\\\ x\le2 .\end{array} Hence, the domain is $ \left( -\infty, 2 \right] .$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.