Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 9 - Inequalities and Problem Solving - 9.1 Inequalities and Applications - 9.1 Exercise Set - Page 583: 59

Answer

$$y=-\frac{7}{9},\:x=\frac{4}{3}$$

Work Step by Step

Solving the system of equations using substitution, we find: $$ \frac{5+3y}{2}+3y=-1 \\ y=-\frac{7}{9}\\ x=\frac{5+3\left(-\frac{7}{9}\right)}{2}\\ x=\frac{4}{3}$$
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