Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 9 - Inequalities and Problem Solving - 9.1 Inequalities and Applications - 9.1 Exercise Set - Page 580: 8


not equivalent

Work Step by Step

$\bf{\text{Solution Outline:}}$ Solve the solution sets of the given statements, \begin{array}{l}\require{cancel} -4t\le12 \\\text{and}\\ t\le-3 .\end{array} If the solution sets are the same, then they are equivalent. Otherwise, they are not equivalent. $\bf{\text{Solution Details:}}$ Using the properties of inequality, the solution of the first inequality is \begin{array}{l}\require{cancel} -4t\le12 \\\\ t\ge\dfrac{12}{-4} \\\\ t\ge-3 .\end{array} Since this is different from the second given inequality, then the given are $\text{ not equivalent .}$
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