Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.

Published by Pearson

ISBN 10: 0-32184-874-8

ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - Test: Chapter 8 - Page 573: 11

Answer

$$x=2,\:y=-\frac{1}{2},\:z=-1$$

Work Step by Step

Solving the equations using matrices, we find: $$\begin{bmatrix}6&2&-4&¦&15\\ -3&-4&2&¦&-6\\ 4&-6&3&¦&8\end{bmatrix} \\ \begin{bmatrix}1&0&0&¦&2\\ 0&1&0&¦&-\frac{1}{2}\\ 0&0&1&¦&-1\end{bmatrix}\\ x=2,\:y=-\frac{1}{2},\:z=-1$$

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