Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - Test: Chapter 8 - Page 572: 2

Answer

$$ y=-\frac{11}{3},\:x=3$$

Work Step by Step

Solving the system of equations using substitution, we find: $$ 4\left(-8-3y\right)-3y=23\\ y=-\frac{11}{3}\\ x=-8-3\left(-\frac{11}{3}\right) \\ x=3$$
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